Model of atom’s
nucleus and table of elements.
Every subsequent element of the
table of elements differs from the previous one in the amount of protons in its
nucleus which is increased by one unit and the amount of neutrons is increased
by several units in general. That means , that there are more neutrons in the
nucleus than protons (without taking into consideration the lightest nucleuses).
The scientific literature doesn’t give any explanation of this strange
correlation of neutrons’ number to the protons’ number.
It should be noted that for the
construction of the model of atom’s nucleus , He nucleuses have the same
energies during the alpha-radioactivity. That’s why let’s place all protons
with the same number of neutrons on the nucleus external shell , that means ,
that on the same energy level only bosons can be found , and they are
considered to be alpha-elements found on the nucleus external shell.
Let’s place the rest of neutrons
inside the nucleus , their task is to weaken the electrostatic field of
protons’ repulsion. Supposing that the nucleus is spherical and protons and
neutrons have the same radiuses , we’ll get a model of nucleus for any element
, which explains the number of neutrons’ ratio to the number of protons , which
follows from the existence of nucleons in the atom’s nucleus .
Radioactive decay is probably
connected with the nucleus compression , because neutrons in the nucleus
capacity weaken radial forces of protons’ repulsion with the growth of an
element’s ordinal number.
If nucleuses mass is primary and
chemical qualities of an atom are secondary , than in the table of elements
atomic weight must change continuously either down on across. Having
constructed the table according to these features we have to leave four empty
places after Lu and Lr in order to observe chemical qualities of elements .
Determination of nucleus charge is probably necessity in discovering elements .
As a matter of fact elements are
considered to be discovered based on their chemical qualities
H
1
He
2
Li
3
Be
4
B
5
C
6
N
7
O
8
F
9
Ne
10
Na
11
Mg12
Al
13
Si
14
P1
5
S
16
Cl
17
Ar
K
19
Ca
20
Sc
21
Ti
22
V
23
Cr
24
Mn
25
Fe
26
Co
27
Ni 28
Cu
29
Zn
30
Ga
31
Ge
32
As
33
Se
34
Br
35
Kr
36
Rb
37
Sr
38
Y
39
Zr
40
Nb
41
Mo
42
Tc
43
Ru
44
Rh
45
Pd
46
Ag
47
Cd
48
In
49
Sn
50
Sb
51
Te
52
I
53
Xe
54
Cs
55
Ba
56
La
57
Ce
58
Pr
59
Nd
60
Pm
61
Sm
62
Eu
63
Gd
64
Tb
65
Dy
66
Ho
67
Er
68
Tu
69
Yb
70
Lu
71
?
72
?
73
?
74
?
75
Hf
76
Ta
77
W
78
Re
79
Os
80
Ir
81
Pt
82
Au
83
Hg
84
Tl
85
Pb
86
Bi
87
Po
88
At
89
Rn
90
Fr
91
Ra
92
Ac
93
Th
94
Pa
95
U
96
Np
97
Pu
98
Am
99
Cm
100
Bk
101
Cf
102
Es
103
Fm
104
Md
105
No
106
Lr
107
In 1891 James Chardwik carried out
researches and with the help of Rezerford’s formula rated nucleuses charges for
platinum-77,4 ; silver-46,3 ; copper-29,3 . These results almost coincided with
ordinal numbers of these elements in the periodic table .
But the last lanthanide are
radioactive ! According to our model of atom’s nucleus radioactivity of the
subsequent after lanthanide elements can be reduced , by bringing a shell
inside the nucleus which consists of 4 protons or 4 alpha-elements.
But then defining the nucleuses charge
of platinum’s atom on Chardwik’s method , we would get again 77,4 ; because
alpha-elements would disperse on the nucleus’s external shell of an atom .
That’s why the question of more
precise definition of nucleus charges of elements following the Hf , is raised
.
This is probably the reason of the
failure to get to the “ island of stability “ and seditious idea comes to the
mine we build atomic electric power stations without knowing the definite
amount of neutrons and protons in the nucleuses of uranium and plutonium .
Список литературы
Hehadzi Filipenka “Engineer” Moscow
N4 1990 , N4 1991.
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